Let three capacitors C1 , C2 and C3 be connected in parallel as shown. The capacitor plates are named A,B,C,D,E and F.
When a battery is connected to the parallel combination, the –ve terminal of the battry supplies a charge –Q which gets divided into –Q1 , –Q2 and –Q3 , in direct proportion to capacitance values, to get stored on plates B, D and F respectively. Simultaneously, the +ve terminal of the battery sucks charge –Q1 , –Q2 and –Q3 from plates A, C and E respectively and therefore creating +ve charges Q1 , Q2 and Q3 on plates A,C and E respectively. Thus, charge is conserved.
So now, plates A, C and E have +Q1 ,+Q2 and + Q3 and plates B, D and F have -Q1 ,-Q2 and -Q3 charges respectively.
The above process continues till the capacitors are fully charged and potential difference across each of them becomes V.
In steady state,
Q1 = C1V
Q2 = C2V
Q3 = C3V
But, by law of conservation of charge i.e Kirchhoff's current law
Q = Q1 + Q2 + Q3
∴ Q = C1 V+ C2 V + C3 V ...(1)
Lets replace the parallel combination by a single capacitor Ceq such that the single capacitor will store the same amount of charge Q on application of same potential difference V.
Then, Q=CeqV ...(2)
Equating (1) and (2)
CeqV = C1 V+ C2 V + C3 V
So, equivalent capacitance for a parallel combination of capacitances is given by the formula
To summarise :-
- All capacitors connected in parallel have same potential difference across them for any value of capacitances.
- Equivalent capacitance value is greater than all the individual capacitance values.
- Equivalent capacitance formula is given by
4. As potential difference is same across all the capacitors in parallel, therefore
Q ∝ C
i.e higher the capacitance value, higher the charge stored on the capacitor and vice-versa.
Related Concepts :-
(1) Capacitors in Series