Two Wattmeter Method - Balanced Load Condition

A three phase balanced voltage is applied on a balanced three phase load makes a current in each of the phases lagging by angle Φ behind the corresponding phase voltage.



two wattmeter method of power measurement connection

The wattmeter connections must be paid special attention. The two wattmeters must be connected in such a way that their current coils are connected in series with the two phases and their pressure coils must be connected between their respective lines and the remaining third line.


two wattmeter method phasor diagram


For wattmeter W1 :-
Current through current coil = IR
Potential difference across voltage coil = VRN- VYN = VRY
Phase difference between IR and VRY  is (300+ Φ)
Thus, reading on wattmeter W1 is
 W1= VRY IR cos(300+ Φ)

For wattmeter W2 :-
Current through current coil = IB
Potential difference across voltage coil = VBN- VYN = VBY
Phase difference between IB and VBY  is (300- Φ)
Thus, reading on wattmeter W2 is
 W2= VBY IB cos(300-Φ)

power measurement by two wattmeter method 

Since the load is balanced, | IR |=| IY |=| IB |= I (Let) and
| VRY |=| VBY |= VL (Let)
∴    W1= VL I cos(300+ Φ)   while  W2= VL I cos(300-Φ)

Thus, the total power is given by
W= W1+ W2 = VL I cos(300+ Φ) + VL I cos(300- Φ)
    = VL I [cos(300+ Φ) + cos(300- Φ) ]
    = 3VL I cos Φ                {  cos(A+B)+cos(A-B)=2cosAcosB }

Thus, with wattmeter connections as shown above, sum of readings of two wattmeters give the total real power.

power factor (p.f ) measurement by two wattmeter method 

W2- W1 = VL I  sin Φ
Dividing the two equations,
 (W2- W1) /(W1+ W2) = tan Φ/3
Thus,   Î¦= tan-1[3 (W2- W1) /(W1+ W2)]
and power factor = cos Î¦
but, power factor nature  i.e  lagging or leading can't be known by this method.  

  
Total reactive power power :-
We already have,
W2- W1 = VLsin Φ
Multiplying by √3, We get
Reactive power = √3 (W2- W1) = √3 VLsin Φ  


Two wattmeter method for leading loads  

As shown above, the value of tan Φ and hence power factor cos Φ can be determined from two wattmeter readings.

tan Î¦=√3 (W2- W1) /(W1+ W2)           ...for lagging power factor

For leading loads the angle becomes negative as per our reference, therefore putting in above formula we get 

tan Î¦=√3 (W1- W2) /(W2+ W1)           ...for leading power factor

If you analyse by putting all possible values of Φ i.e from 00 to 900  in W1 and W2 , you will find that  Wis the higher reading wattmeter in lagging power factor case, and Wis the higher reading wattmeter in  leading power factor case .